y = 3x + 2
2y - 14 = - 4x
Since the first equation is solved for y, and since y is equal
to 3x + 2, we put that in parentheses like this (3x + 2), then
we take the other equation and instead of y put what y equals,
namely (3x + 2). Then solve for x
2y - 14 = -4x
2(3x + 2) - 14 = -4x
6x + 4 - 14 = -4x
6x - 10 = -4x
6x + 4x = 10
10x = 10
x = 1
Now take the first equation
y = 3x + 2
and substitute (1) for x
y = 3(1) + 2
then finish the right side
y = 3 + 2
y = 5
So the solution is (x,y) = (1,5)
Edwin