Question 490704: Find equation of line given these two points
(-3,-2) (2,6)
So far I have M = 8/5 [6-(-2)/2-(-3)]
y = 8/5x + b
6 = 8/5(2) + b
now what ?
Found 2 solutions by John10, MathLover1:
Answer by John10(297)   (Show Source):
You can put this solution on YOUR website! Your slope is CORRECT m = 8/5
After that, you will use the slope-point formula as below:
y - yo = m(x - xo)
y - 6 = 8/5(x - 2)
y - 6 = 8x/5 - 16/5
y = 8x/5 - 16/5 + 6
y = 8x/5 - 16/5 + 30/5 ------------>(6 is replaced by 30/5 = 6)
y = 8x/5 + 14/5 which is what you are looking for!
John10:)
Answer by MathLover1(20850)  (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, -2) and (x2, y2) = (2, 6).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(1.6)x + (2.8)
Your graph:
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