You can
put this solution on YOUR website! Factor
x³ + 5x + 3x² + 15
Factor the first two terms only by
taking out x
x(x² + 5) + 3x² + 15
Factor the last two terms only by
taking out 3
x(x² + 5) + 3(x² + 5)
Now you see that the term
x(x² + 5) and the term
3(x² + 5) have the common
factor (x² + 5)
x(x² + 5) + 3(x² + 5)
So factor out the red factor (x² + 5)
on the left and leave the black factors
in parentheses on the right:
(x² + 5)(x + 3)
Edwin