SOLUTION: if i have a triangle with sides 40cm, 32cm, and 15.3cm and an angle of 112 degrees where the 32cm side and 15.3cm side meet, what is the measure of the angle opposite of the side t
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Question 490397: if i have a triangle with sides 40cm, 32cm, and 15.3cm and an angle of 112 degrees where the 32cm side and 15.3cm side meet, what is the measure of the angle opposite of the side that is 15.3cm? Answer by cleomenius(959) (Show Source):
You can put this solution on YOUR website! You can use the law of sines
40/sin112 = 15.3 /x
x = sin 20.77, the angle opposite the 15.3 cm side.
For a check, using the law of sines the angle opposite the 32 cm side = 47.88.
47.88 degrees + 20.77 degrees + 112 degrees = 180.65, approx 180.
Cleomenius.
