Question 49030: 2r + 5 < -1, 3t ≥ 6t + 12,1 + 2x < 2(x-1)
Answer by AnlytcPhil(1807)   (Show Source):
You can put this solution on YOUR website! 2r + 5 < -1
Add -5 to both sides
2r + 5 < -1
-5 -5
---------------
2r < -6
Divide both sides by 2, which is
a positive number so we DO NOT
reverse the inequality symbol
2r -6
---- < ----
2 2
r < -3
Sometimes this is written (-¥, -3)
------------------------------
3t > 6t + 12
add -6t to both sides
3t > 6t + 12
-6t -6t
---------------
-3t > 12
Divide both sides by -3, which is
a negative number, so we DO
reverse the inequality symbol from
> to
-3t 12
----- < ----
-3 -3
t < -4
Sometimes this is written (-¥,-4]
---------------------------------
1 + 2x < 2(x - 1)
1 + 2x < 2x - 2
Add -2x to both sides
1 + 2x < 2x - 2
-2x -2x
--------------------
1 < -2
Since 1 is not less than -2
this has no solution.
Sometimes this is written Æ
Edwin
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