SOLUTION: HELP !!! I NEED UR HELP !! A straight line with equation 2y=kx+h passes through the points (-3,6) and (1,11). Find the value of k and h.

Algebra ->  Graphs -> SOLUTION: HELP !!! I NEED UR HELP !! A straight line with equation 2y=kx+h passes through the points (-3,6) and (1,11). Find the value of k and h.      Log On


   

Question 490189: HELP !!! I NEED UR HELP !!
A straight line with equation 2y=kx+h passes through the points (-3,6) and (1,11). Find the value of k and h.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+2y+=+kx+%2B+h+
passes through the points
(-3,6) and (1,11)
----------------
Plug in (x,y) = (-3,6)
+2%2A6+=+k%2A%28-3%29+%2B+h+
(1) +12+=+-3k+%2B+h+
and
(x,y) = (1,11)
+2%2A11+=+k%2A1+%2B+h+
(2) +22+=+k+%2B+h+
-----------------
Rewrite both equations in reverse order
(1) +h+-+3k+=+12+
(2) +h+%2B+k+=+22+
Subtract (1) from (2)
(2) +h+%2B+k+=+22+
(1) +-h+%2B+3k+=+-12+
+4k+=+10+
+k+=+5%2F2+
and, since
+h+%2B+k+=+22+
+h+%2B+5%2F2+=+22+
+2h+%2B+5+=+44+
+2h+=+39+
+h+=+39%2F2+
----------------
check:
Does the equation pass through the points?
+2y+=+kx+%2B+h+
+2y+=+%285%2F2%29%2Ax+%2B+39%2F2+
+y+=+%285%2F4%29%2Ax+%2B+39%2F4+
(-3,6)
+6+=+%285%2F4%29%2A%28-3%29+%2B+39%2F4+
+6+=+-15%2F4+%2B39%2F4+
+6+=+24%2F4+
+6+=+6+
OK
(1,11)
+y+=+%285%2F4%29%2Ax+%2B+39%2F4+
+11+=+%285%2F4%29%2A1+%2B+39%2F4+
+11+=+44%2F4+
+11+=+11+
OK