SOLUTION: An ocean liner, traveling at 30 km/h leaves port at 7:00am. At 10:00 am, a helicopter leaves the same port and travels the same route at 66 km//h. At what time will the helicopter
Question 490162: An ocean liner, traveling at 30 km/h leaves port at 7:00am. At 10:00 am, a helicopter leaves the same port and travels the same route at 66 km//h. At what time will the helicopter overtake the liner? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Write an equation for each
The liner:
The helicopter:
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Wait until the helicopter leaves the port,
and start a stopwatch. Also, figure out how much
of a head start the liner got (3 hrs) km
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Both will travel for the same amount of time, but
the liner will travel km less distance
(1)
(2)
This is 2 equations and 2 unknowns, so it's solvable
Substitute (1) into (2)
(2)
(2)
(2) hrs
This is the time elapsed from when the
helicopter leaves at 10 am, so it catches up
with the line at 12:30
check answer:
(1)
(1)
and
(2)
(2)
(2)
(2)
OK
