You can put this solution on YOUR website! i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i
i^4 = (i^2)(i^2) = (-1)(-1) = 1
i^5 = (i^2)(i^2)i = i
i^6 = (i^2)^3 = (-1)^3 = -1
i^7 = (i^2)^3 * i = -i
See a pattern?
Every imaginery number to an odd power = +- i
Every imaginery number to an even power including zero = +- 1
To find the value ~> just simplify
ex.) i^49 we know that this will equal either 'i' or '-i'
(i^7)^7 = (i^2*i^2*i^2*i)^7 = (-i)^7 = i
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