SOLUTION: How do you solve [(a^2/3*b^-2)^3]^-1

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Question 489514: How do you solve [(a^2/3*b^-2)^3]^-1
Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
Nothing to solve, but you simplify it by knowing that exponents of exponents simply multiply.
so becomes (a^(2/3)*b^(-2))^-3
and due to distribution of exponent over factors,
on to a^(-2)*b^(6)
=(b^6)/a^2