Question 489501: 1) A) given that set A={0,1,2,3,4,5,6}, find the number of subsets that A has.
B) Given the universal set S = { -4,-3,-2,-1,0,1,2,3,4} and B= {-1,0,1,2,3}, find B'
2) A) how many 5-letter arrangements can be formed from the letters in the word table?
B) if you choose one of these words, what is the probability that the last letter is e?
3) there are 7 green balls and 3 red balls in an urn. Three balls are drwan individually and replaced. Set up a probability distribution for x, the number of red balls selected
4) A box contains 3 red balls and 4 white balls. You draw 4 balls from the box without replacing them. Set up a probability distribution for x, the number of red balls selected
5) You are dealt a 13- card bridge hand from a deck of 52 cards.
a) what is the probability of being dealt 8 card from the same suit?
b) what is the probability of being dealt 6 hearts?
C) If you are dealt 7 hearts, what is the probability that your partner has atleast 1 heart?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1) A) given that set A={0,1,2,3,4,5,6}, find the number of subsets that A has.s
Ans: 2*6 = 64 subsets
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B) Given the universal set S = { -4,-3,-2,-1,0,1,2,3,4} and B= {-1,0,1,2,3}, find B'
Ans: B' = {4,-4,-3,-2,}
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2) A) how many 5-letter arrangements can be formed from the letters in the word table?
Ans: 5! = 120
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B) if you choose one of these words, what is the probability that the last letter is e?
Ans: 4!/5! = 1/5
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3) there are 7 green balls and 3 red balls in an urn. Three balls are drawn individually and replaced. Set up a probability distribution for x, the number of red balls selected.
Binomial Problem with n = 3 ; p = 3/7 : q = 4/7
P(x = 0) = (4/7)^3
P(x = 1) = 7C1(3/7)(4/7)^2 =
P(x = 2) = 7C2(3/7)^2(4/7) =
P(x = 3) = 7C3(3/7)^3 =
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4) A box contains 3 red balls and 4 white balls. You draw 4 balls from the box without replacing them. Set up a probability distribution for x, the number of red balls selected
Not a binomial Problem because of no replacing.
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P(x = 0) = 4C4/7C4
P(x = 1) = [3C1*4C3]/7C4
P(x = 1) = [3C2*4C2]/7C4
etc.
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5) You are dealt a 13- card bridge hand from a deck of 52 cards.
a) what is the probability of being dealt 8 cards from the same suit?
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# of ways to succeed : 4*13C8*39C5
# of random results: 52C13
P(8 cards of same suit) = [4*13C8*39C5]/52C8
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b) what is the probability of being dealt 6 hearts?
# of ways to succeed: [13C6*39C7]/52C13
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C) If you are dealt 7 hearts, what is the probability that
your partner has at least 1 heart?
P(at least one heart) = 1 - P(no hearts)
= 1 - {39C13/52C13]
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Cheers,
Stan H.
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