Question 489141: One-fifth of sum of two consecutive integers is 64 less than the smaller integer.
Find the smaller of the two integers Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 1/5(n+(n+1)=n-64
1/5(2n+1)=n-64
2n+1=5n-320
321=3n
n=107
n+1=108
The integers are 107 and 108..