SOLUTION: Find three consecutive integers so that twice the first added to five times the second exceeds three times the third by 51.

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Question 4886: Find three consecutive integers so that twice the first added to five times the second exceeds three times the third by 51.
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
Let smallest integer be x
next is therefore x+1
largest is x+2.

(two times smallest + five times middle) - three times biggest = 51
2x + 5(x+1) - 3(x+2) = 51
2x + 5x +5 - 3x - 6 = 51
4x - 1 = 51
4x = 52
x = 13

so, the numbers are 13, 14, 15.

jon.