SOLUTION: Suppose the length and width of the rectangle are doubled. what effect would this have on the area? Justify your answer. rectangle dimensions = 17ft L

Algebra ->  Rectangles -> SOLUTION: Suppose the length and width of the rectangle are doubled. what effect would this have on the area? Justify your answer. rectangle dimensions = 17ft L       Log On


   

Question 488537: Suppose the length and width of the rectangle are doubled. what effect would this have on the area? Justify your answer. rectangle dimensions = 17ft L
4 ft W
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
A = L * W
this means area equals length times width.
if you double the length and you double the width, the formula becomes:
A = 2 * L * 2 * W which is the same as:
A = 2 * 2 * L * W which is the same as:
A = 4 * L * W
if you double the length and the width, you are quadrupling the area.
this is because 2 * 2 = 4.
an example:
L = 2 and W = 4
Area = 2 * 4 = 8
double the length and double the width to get:
L = 4 and W = 8
Area = 4 * 8 = 32
32 is 4 times as large as 8.
you doubled the length and the width and you quadrupled the area.
this is because 2 * 2 = 4
if you tripled the length and doubled the width, then the area would be 6 times as large because 2 * 3 = 6
an example:
L = 2 and W = 4
Area = 2 * 4 = 8
double the length and triple the width to get:
L = 4 and W = 12
Area = 4 * 12 = 48
48 is 6 times as big as 8.
what you did was:
L * W = Area
you doubled the length and tripled the width to get:
2 * L * 3 * W = Area
this becomes:
2 * 3 * L * W = Area which becomes:
6 * L * W = Area
the area becomes 6 times as large because 2 * 3 = 6.