Question 48816This question is from textbook Algebra
: If y varies inversely as x^2, and y = 2 when x = 4, what is the constant of variation? This question is from textbook Algebra
You can put this solution on YOUR website! ans: y varies inversely as x^2
y=k/x^2 ,k is constant of variation (as y increases x^2 decreases)
y*x^2=k
Now y=2 and x=4 substituting we get
2*4^2=k
2*16=k
32=k ans.