SOLUTION: how do you condense 2ln(x-3) + ln(x+2) - 6lnx
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Question 488087
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how do you condense 2ln(x-3) + ln(x+2) - 6lnx
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lwsshak3(11628)
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how do you condense 2ln(x-3) + ln(x+2) - 6lnx
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2ln(x-3) + ln(x+2) - 6lnx
=ln(x-3)^2+ln(x+2)-lnx^6
=ln[(x-3)^2*(x+2)/(x^6)]