SOLUTION: the perimeter is 44 ft. the area is 120 sq ft. How do you find the length and the width using the formula P=2l + 2w?

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Question 487870: the perimeter is 44 ft. the area is 120 sq ft. How do you find the length and the width using the formula P=2l + 2w?
Answer by John10(297) (Show Source):
You can put this solution on YOUR website!
Hint: You have to use two formulas for the perimeter and area:
P = 2(L +W) = 44
A = L*W = 120
Solve the system of two equations, you will find L and W.
From the perimeter formula:
L +W = 22 or L = 22 - w
Substitute L = 22 - w into the area formula:
W(22-W) = 120
-w^2 +22w - 120 = 0
w^2 - 22w + 120 = 0
(w - 10)(w - 12) =0
W = 10 or w = 12
If w = 10 then L = 22 -10 = 12
If w = 12 then L = 22 - 12 = 10 (this case is not correct because the width is more than the length)
Thus the width is 10 ft
The length is 12 ft.
John10:)