SOLUTION: I don't actually understand how to do logarithms, I've been taught but I cannot understand them, so would you please be able to help me by showing me how to solve for x: log x + lo
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-> SOLUTION: I don't actually understand how to do logarithms, I've been taught but I cannot understand them, so would you please be able to help me by showing me how to solve for x: log x + lo
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Question 487640: I don't actually understand how to do logarithms, I've been taught but I cannot understand them, so would you please be able to help me by showing me how to solve for x: log x + log 2x = log 50.
Thanking You.
Tracey Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! log x + log 2x = log 50
log x + log 2x - log 50=0
place under a single log using log rules of multiplication and division
log(x*2x/50)=0
Convert to exponential form: base(10) raised to log of number(0)=number (x*2x/50)
10^0=(x*2x/50)
1=2x^2/50
2x^2=50
x^2=50/2=25
x=±√25=±5
x=-5 (reject, x>0)
or
x=5 (ans)
Check:
log x + log 2x = log 50
log 5+log10=log 5*10=log 50
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