SOLUTION: the length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. I have NO Clues how to do this a

Algebra ->  Rectangles -> SOLUTION: the length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. I have NO Clues how to do this a      Log On


   

Question 48740: the length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
I have NO Clues how to do this any help please
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 2w + 2
2w+%2B+2l+=+Perimeter
2w+%2B+4w+%2B+4+=+34
6w+=+30
w+=+5
width = 5
length = 2*5 + 2 = 12