SOLUTION: 51 = 400e^(−0.6x) I want to know how to solve for x using logarithms. Thank you for your time!!!

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Question 487347: 51 = 400e^(−0.6x) I want to know how to solve for x using logarithms.
Thank you for your time!!!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
51 = 400e^(−0.6x)
51/400=e^(-0.6x)
take ln of both sides
ln 51-ln 400=-0.6xlne
log of base=1
-2.0596=-0.6x
x=-2.0596/-0.6
x=3.4327
Check:
400e^(−0.6x=400e^(−0.6*3.4327)=400*1.275=51.00