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Question 487316: the sum of three integers is 232. the sum of the first and second integers exceeds the third by 92. the third integer is 48 less than the first. find the three integers
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! the sum of three integers is 232.
a + b + c = 232
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the sum of the first and second integers exceeds the third by 92.
a + b = c + 92
a + b - c = 92
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the third integer is 48 less than the first.
c = a - 48
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The first and 2nd equations for elimination
a + b + c = 232
a + b - c = 92
----------------subtraction eliminates a and b, find c
2c = 140
c = 70, the 3rd digit
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The third equation
a - 48 = 70
a = 70 + 48
a = 118, the first digit
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Find the 2nd digit
118 + b = 70 + 92
b = 162 - 118
b = 44, the 2nd digit
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Check: 118 + 44 + 70 = 232
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