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Question 48707: Please im asking someone to please give me a helping hand with the following questions. I would really really appreciate some help.
1)Identify the horizontal asymptotes for the fuction of f(x)= x-5/x+1
2)Which type of variation is represented by a1/b1= a2/b2
a. inverse
b. direct
c. joint
d. none
3)Which type of variation is represented by a1 b1= b2 a2
a. inverse
b. direct
c. joint
d. none
4)Suppose y varies directly as x. If y = 5 when x = 15, find x when y = 9.
a. 3
b. 6
c. 12
d. 27
5)Suppose y varies inversely as x. If y = 2 when x = 14, find y when x = 7.
a. 1
b. 4
c. 6
d. 8
6)Suppose y varies jointly as x and z. If y = 10 when x = 2 and z = 4, find y when x = 4 and z = 3.
a. 6
b. 12
c. 15
d. 20
7)Simplify x^2-5x-24/6x +2x^2 * 5x^2/8-x
8)simplify x^2-3x/x^2-25 * x^2+4x-5/x^2-4x+3
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1)Identify the horizontal asymptotes for the fuction of f(x)= x-5/x+1
horizontal asymptote = x/x= 1; y=1
2)Which type of variation is represented by a1/b1= a2/b2
a1 and a2 are direct; b1 and b2 are direct; a1 and b2 are inverse b1 and a2 are inverse. The Site "MathWorld" says there is no such thing as "joint" variation.
a. inverse
b. direct
c. joint
d. none
--------------------------------------
3)Which type of variation is represented by a1 b1= b2 a2
a1, a2, b2 direct; b1, b2,a2 direct; a1, b1 indirect; b2,a2 indirect
a. inverse
b. direct
c. joint
d. none
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4)Suppose y varies directly as x. If y = 5 when x = 15, find x when y = 9.
direct variation implie y=kx
5=k(15)
k=1/3
y=(1/3)x
If y=9, 9=(1/3)x
x=27
a. 3
b. 6
c. 12
d. 27
---------------------------------
5)Suppose y varies inversely as x. If y = 2 when x = 14, find y when x = 7.
inversely implied y=k/x
2=k/14
k=28
y=28/x
If x=7 then y=28/7=4
a. 1
b. 4
c. 6
d. 8
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6)Suppose y varies jointly as x and z. If y = 10 when x = 2 and z = 4, find y when x = 4 and z = 3.
jointly ????????
a. 6
b. 12
c. 15
d. 20
---------------------------------
7)Simplify x^2-5x-24/6x +2x^2 * 5x^2/8-x
Factor where you can as follows:
[(x-8)(x+3)]/[2x(3+x)]
= (x-8)/2x]
= -5x/2
--------------------
Cheers,
Stan H.
8)simplify x^2-3x/x^2-25 * x^2+4x-5/x^2-4x+3
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