Question 486869: Find four consecutive even integers such that the product of the first and fourth is equal to the square of the second? Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! Let x, x+2, x+4, x+6 be the 4 integers.
x(x+6)=(x+2)^2
x^2+6x=x^2+4x+4
x^2-x^2+6x-4x=4
2x=4
x=4/2
x=2 ans. for the first integer.
2+2=4 ans. for the second integer.
2+6=8 ans. for the foyrth integer.
Proof:
2*8=4^2
16=16