SOLUTION: {{{2x > x + 10 > -x}}} I have looked all over the internet for the answer to 'how' this kind of problem is solved. I read in the book that the answer is x > 10, but why? Than

Algebra ->  Inequalities -> SOLUTION: {{{2x > x + 10 > -x}}} I have looked all over the internet for the answer to 'how' this kind of problem is solved. I read in the book that the answer is x > 10, but why? Than      Log On


   



Question 48673: 2x+%3E+x+%2B+10+%3E+-x
I have looked all over the internet for the answer to 'how' this kind of problem is solved. I read in the book that the answer is x > 10, but why?
Thanks

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
2x > x + 10 > -x has 2 parts:

we need to work out +2x+%3E+x+%2B+10+ and then also +x+%2B+10+%3E+-x+.

So, +2x+%3E+x+%2B+10+
+x+%3E+10+

And +x+%2B+10+%3E+-x+
+10+%3E+-2x+
which is +-2x+%3C+10+ just re-written... be careful with that inequality sign.

This becomes +x+%3E+10%2F%28-2%29+
+x+%3E+-5+

So the answers are "x has to be greater than -5" but also, the first one says "x has to be greater than 10"

We cannot have both these answers since x=2 for example does not satisfy "x>10". So the one answer we are allowed to have is x>10 since anything greater than 10 satisfies both parts of the question.

jon.