SOLUTION: vertex of y = x^2 - 4x + 5?
Algebra
->
Signed-numbers
-> SOLUTION: vertex of y = x^2 - 4x + 5?
Log On
Algebra: Operations with Signed Numbers
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Signed-numbers
Question 486568
:
vertex of y = x^2 - 4x + 5?
Answer by
CubeyThePenguin(3113)
(
Show Source
):
You can
put this solution on YOUR website!
Complete the square.
x^2 - 4x + 5 = (x^2 - 4x + 4) + 1 = (x - 2)^2 + 1
The vertex is (2, 1)