SOLUTION: (x+7)(x-1)=(x+1)^2 i got to this step: X^2-x+7x-(x+1)^2+7=0 I do not uderstand what to do after the exponent is confusing me and i will really apreciate your help/advice thank

Algebra ->  Linear-equations -> SOLUTION: (x+7)(x-1)=(x+1)^2 i got to this step: X^2-x+7x-(x+1)^2+7=0 I do not uderstand what to do after the exponent is confusing me and i will really apreciate your help/advice thank       Log On


   

Question 486233: (x+7)(x-1)=(x+1)^2
i got to this step: X^2-x+7x-(x+1)^2+7=0
I do not uderstand what to do after the exponent is confusing me and i will really apreciate your help/advice thank you in adcanced.
Found 2 solutions by mananth, chessace:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B7%29%28x-1%29=%28x%2B1%29%5E2
you should expand the brackets
x%28x-1%29%2B7%28x-1%29=x%5E2%2B2x%2B1
x%5E2-x%2B7x-7=x%5E2%2B2x%2B1
re arrange the terms
x%5E2-x%5E2%2B6x-2x-8=0
4x-8=0
4x=8
x=2

Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
First off, you got the final sign wrong, it's -7.
You need to expand the (x+1)^2 and collect terms:
x^2 +6x -(x^2 + 2x + 1) -7 = 0
Collect terms again (you do it too):
4x - 8 = 0
More little steps for you results in:
x = 2