SOLUTION: A farmer keeps sheep and chickens. In the farmyard there are 68 animals with a total of 270 legs. Assuming every chicken has exactly two legs and each sheep has exactly four legs,

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A farmer keeps sheep and chickens. In the farmyard there are 68 animals with a total of 270 legs. Assuming every chicken has exactly two legs and each sheep has exactly four legs,       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 485893: A farmer keeps sheep and chickens. In the farmyard there are 68 animals with a total of 270 legs. Assuming every chicken has exactly two legs and each sheep has exactly four legs, how many chickens and how many sheep are there in the farmyard?
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
Let x chickens
Let y sheep
system%28x%2By=68%2C2x%2B4y=270%29
divide the second equation by 2
system%28x%2By=68%2Cx%2B2y=135%29
subtract the first equation from the second
y=67 sheep
Substitute y=67 into the first equation
x%2B67=68
x=1chicken
A farmer has 1 chicken and 67 sheep