SOLUTION: {(-3, 2), (-1, 3), (-1, 2), (0, 4), (1, 1)} {-(3, 2), (-2, 3), (-1, 1), (0, 4), (0, 1)} {(- 3, 3), (-2, 3), (-1, 1), (0, 4), (0, 1) }{-(3, 2), (-2

Algebra ->  Rational-functions -> SOLUTION: {(-3, 2), (-1, 3), (-1, 2), (0, 4), (1, 1)} {-(3, 2), (-2, 3), (-1, 1), (0, 4), (0, 1)} {(- 3, 3), (-2, 3), (-1, 1), (0, 4), (0, 1) }{-(3, 2), (-2      Log On


   



Question 485437: {(-3, 2), (-1, 3), (-1, 2), (0, 4), (1, 1)} {-(3, 2), (-2, 3), (-1, 1), (0, 4), (0, 1)} {(- 3, 3), (-2, 3), (-1, 1), (0, 4), (0, 1) }{-(3, 2), (-2, 3) , -(1, 2), (0, 4), (1, 1)} Determine which relation is a function. I am so confused!
Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
A function is a relation in which value of independent variable (1st of pair) appears at most once, so
{(-3, 2), (-1, 3), (-1, 2), (0, 4), (1, 1)} NO (-1 twice)
{-(3, 2), (-2, 3), (-1, 1), (0, 4), (0, 1)} NO (0)
{(- 3, 3), (-2, 3), (-1, 1), (0, 4), (0, 1)} NO (0)
{-(3, 2), (-2, 3) , -(1, 2), (0, 4), (1, 1)} OK assuming "-(1,2)" means (-1,-2).
"-(1,2)" is not a standard format for expressing an ordered pair; i.e., don't use it and complain if others do.
No wonder you were confused.