Question 48529: solve the system algebraically:
x^2+y^2=20 x^2-2y^2=8
thanks for helping me with this
i hope you can help
;) Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! x~2+y~2=20
x~2-2y~2=8 now subtract these equations we get
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3y~2=12 or y~2=12/3 or y~2=4 or y=2 then x~2+2*2=20 or x~2+4=20 or x~2=16 or x=4