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Question 485279: Write the equation of a line perpendicular to the line y = 3x + 9 and containing the point (6, -4)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Write the equation of a line perpendicular to the line y = 3x + 9 and containing the point (6, -4)
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Standard form for a straight line: y==mx+b, m=slope, b=y-intercept
y = 3x + 9
Slope m of given line=3
Slope of line perpendicular to given line=negative reciprocal=-1/3
Equation:
y=-x/3+b
solving for b using given point (6,-4)
-4=-6+b
b=2
Equation:
y=-x/3+2
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