SOLUTION: The system of linear equations has an unique solution. Find the solution using Gaussian elimination of Gauss-Jordan elimination. These equations use sub-exponents, though. 2x

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Question 48509This question is from textbook College Algebra
: The system of linear equations has an unique solution. Find the solution using Gaussian elimination of Gauss-Jordan elimination.
These equations use sub-exponents, though.
2x sub(1) + x sub(2) = 7
2x sub(1) - x sub(2) + x sub(3) = 6
3x sub(1) -2x sub(2) +4x sub(3) = 11
How do you treat these sub-exponents?
Thank you so much!
This question is from textbook College Algebra

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
The system of linear equations has an unique solution. 
Find the solution using Gaussian elimination of Gauss-Jordan
elimination.

These equations use sub-exponents, though.

2x1 +  x2       =  7
2x1 -  x2 +  x3 =  6
3x1 - 2x2 + 4x3 = 11

How do you treat these sub-exponents?

They're called "subscripts" not "sub-exponents".  It is exactly 
the same as the problem

2x +  y      =  7
2x -  y +  z =  6
3x - 2y + 4z = 11

Which has solution (x, y, z) = (3, 1, 1)

So your problem has solution (x1, x2, x3) = (3, 1, 1)

You see, in practical real life problems that are done in, say, 
Excel, there may be more than 26 unknowns.  But there are only 26 
alphabet letters.  So to fix the problem they use numbered 
subscripts for the same letter.  The book could have given you 
just x, y and z, but the author and your teacher wanted to 
introduce to you subscripted variables. It's possible to run out
of letters, but not subscripts.

Edwin