SOLUTION: Please help me solve this equation step by step: {{{ sqrt(3+2x) + sqrt(2-2x=3) }}}

Algebra ->  Square-cubic-other-roots -> SOLUTION: Please help me solve this equation step by step: {{{ sqrt(3+2x) + sqrt(2-2x=3) }}}      Log On


   

Question 485048: Please help me solve this equation step by step:
+sqrt%283%2B2x%29+%2B+sqrt%282-2x=3%29+
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(3+2x) + sqrt(2-2x)=3
√(3+2x)=3-√(2-2x)
square both sides
3+2x=9-6√(2-2x)+2-2x
isolate radical
6√(2-2x)=9+2-2x-2x-3
6√(2-2x)=-4x+8
square both sides again
36(2-2x)=16x^2-64x+64
72-72x=16x^2-64x+64
combine like terms then set expression=0
16x^2+8x-8=0
2x^2+x-1=0
(x+1)(2x-1)=0
x+1=0
x=-1
or
2x-1=0
x=1/2