SOLUTION: solve the system algebraically: x^2+y^2=20 x^2-2y^2=8 please help me thanks a lot
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Question 48492
:
solve the system algebraically: x^2+y^2=20 x^2-2y^2=8
please help me
thanks a lot
Answer by
onespal(2)
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1st, get the value of x by transposing the y to the left side
x^2=20-y^2 then substitute to the y of the 2nd equation
20-y^2-2y^2=8 >>>> -3y^2=-12
---- --- = y^2= 4 >> y=2
-3 -3