SOLUTION: the lead car in a race is .5 miles ahead of the second ar and is traveling 2 mies per hour faster after x mohours will the lead car is d(x) miles in front of the second car where d
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Question 484858: the lead car in a race is .5 miles ahead of the second ar and is traveling 2 mies per hour faster after x mohours will the lead car is d(x) miles in front of the second car where d(x) =
a.)(2x) - 5
b.) 2x + 5
c.)(2x).5
d.) 2x + .5 Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! the lead car in a race is .5 miles ahead of the second ar and is traveling 2 mies per hour faster after x mohours will the lead car is d(x) miles in front of the second car where d(x) =
a.)(2x) - 5
b.) 2x + 5
c.)(2x).5
d.) 2x + .5
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The initial separation is 0.5 miles at x=0 hours.
For every hour, the lead car will gain 2 more miles on the second car.
After x hours, the separation will be:
d(x) = 2x + 0.5
So the answer is d).
