Question 484728: in pharmacologic research a variety of clinical chemistry measurements are routinely monitored closely for evidence of side effects of the medications under study. suppose typical blood-glucose levels are normally distributed, with mean = 90 mg/dL and standard deviation = 38 mg/dL.
2 part question
if the normal range is 65-120mg/dL, then what percentage of values will fall in the normal range?
frequently tests that yield abnormal results are repeated for confirmation. what is the probability that for a normal person a test will be at least 1.5 times as high as the upper limit of normal on two separate occasions?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! suppose typical blood-glucose levels are normally distributed, with mean = 90 mg/dL and standard deviation = 38 mg/dL.
2 part question
if the normal range is 65-120mg/dL, then what percentage of values will fall in the normal range?
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z(65) = (65-90)/38 = -0.6579
z(120) = (120-90)/38 = 0.7895
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P(normal range) = P(-0.6579 <= z <= 0.7895)
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frequently tests that yield abnormal results are repeated for confirmation. what is the probability that for a normal person a test will be at least 1.5 times as high as the upper limit of normal on two separate occasions?
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1.5*120 = 180
z(180) = (180-90)/38 = 2.3684
P(x >= 180) = P(z >= 2.3684) = 0.0089
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P(that high on two separate occasions) = 0.0089^2 = 0.000079791...
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Cheers,
Stan H.
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