SOLUTION: What is the domain and range of the function ... f(x)= square root of (3-x)/(x-2)(x^2+5)

Algebra ->  Functions -> SOLUTION: What is the domain and range of the function ... f(x)= square root of (3-x)/(x-2)(x^2+5)       Log On


   

Question 484120: What is the domain and range of the function ... f(x)= square root of (3-x)/(x-2)(x^2+5)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the domain and range of the function ... f(x)= square root of (3-x)/(x-2)(x^2+5)
**
√(3-x)/(x-2)(x^2+5)
3-x≥0
-x≥-3
x≤3
..
(x-2)(x^2+5=0
x-2=0
x≠2
x^2+5=0
x^2=-5 (non-real root)
Asymptote: x-axis or y=0
..
Domain: (-∞, 2) U (2, ∞)
Range: (-∞, 0) U (0, ∞)