SOLUTION: what is the domain and range of the function.... f(x)= 4/x + 8/(x+2)

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Question 484114: what is the domain and range of the function.... f(x)= 4/x + 8/(x+2)
Answer by lwsshak3(11628) About Me  (Show Source):
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what is the domain and range of the function.... f(x)= 4/x + 8/(x+2)
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f(x)= 4/x + 8/(x+2)
y=4(x+2)+8x/(x(x+2))
y=4x+8+8x/x(x+2)
y=12x+8/x(x+2)
x-intercept
set y=0
12x+8=0
12x=-8
x=-8/12=-2/3
zeros:
x+2=0
x≠-2
x≠0
Asymptote: x-axis or y=0, but curve crosses x-axis at x=-2/3
Domain: (-∞, -2) U (-2, 0) U (0, ∞)
Range: (-∞, ∞)