SOLUTION: Could you please help me find the inverse of the following function? f(x) = sqrt(3)(x-1) + 2 This is what I have. Is it correct? y-2 = sqrt(3)(x-1) (y-2)sqrt(3) = x-1 (

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Question 483933: Could you please help me find the inverse of the following function?
f(x) = sqrt(3)(x-1) + 2
This is what I have. Is it correct?
y-2 = sqrt(3)(x-1)
(y-2)sqrt(3) = x-1
(y-2)(y-2)(y-2) = x-1
(y^2-2y-2y+4)(y-2) = x-1
y^3-2y^2+4y^2-8y+4y-8 = x-1
y^3+2y^2-6y-8 = x-1
y^3+2y^2-6y-7 = x
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
Could you please help me find the inverse of the following function?
f(x) = sqrt(3)(x-1) + 2
This is what I have. Is it correct?
y-2 = sqrt(3)(x-1)
(y-2)sqrt(3) = x-1
(y-2)(y-2)(y-2) = x-1
(y^2-2y-2y+4)(y-2) = x-1
y^3-2y^2+4y^2-8y+4y-8 = x-1
y^3+2y^2-6y-8 = x-1
y^3+2y^2-6y-7 = x
***
To find the inverse of a function, interchange x and y, then solve for y. In effect you are solving for x in terms of y.
f(x)=sqrt(3)(x-1) + 2
y=sqrt(3)(x-1) + 2
x=√3(y-1)+2
x-2=√3(y-1)
y-1=(x-2)/√3
y=((x-2)/√3)+1 (inverse of f(x))