SOLUTION: I'm stumped here and know it has to be a sign thing.... Problem = x-xy(y^0-x^-3) if x= -2 and y = 3 -2-(-2x3)(1-(-2^-3) -2-(-6)[(1 - (-1/8)] -2+6(1 and 1/8) -2 + 6 and

Algebra ->  Absolute-value -> SOLUTION: I'm stumped here and know it has to be a sign thing.... Problem = x-xy(y^0-x^-3) if x= -2 and y = 3 -2-(-2x3)(1-(-2^-3) -2-(-6)[(1 - (-1/8)] -2+6(1 and 1/8) -2 + 6 and       Log On


   

Question 48377This question is from textbook Saxon Algebra 1
: I'm stumped here and know it has to be a sign thing....
Problem = x-xy(y^0-x^-3) if x= -2 and y = 3
-2-(-2x3)(1-(-2^-3)
-2-(-6)[(1 - (-1/8)]
-2+6(1 and 1/8)
-2 + 6 and 1/8
4 and 1/8
but answer is supposed to be 19/4
?????? Help.... This question is from textbook Saxon Algebra 1

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x - xy(y^0 - x^(-3)) if x = -2 and y = 3
-2 - (-2)(3)(1 - (-2)^(-3))
-2 + 6(1 + 1/8)
-2 + 6(9/8)
-16/8 + 54/8
38/8 = 19/4