You can put this solution on YOUR website! Find the remaining trigonometric functions of θ if csc(θ) = 17/8 and cos(θ) < 0.
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csc positive and cos negative , so theta in QII
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csc = r/y ; so r = 17 and y = 8
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therefore x = sqrt[17^2-8^2] = sqrt[225] = 15
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But x is negative in QII so x = -15
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sin = y/r = 8/17
cos = x/r = -15/17
tan = y/x = -8/15
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csc = r/y = 17/8
sec = r/x = -17/15
cot = x/y = -15/8
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Cheers,
Stan H.
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