SOLUTION: Hi here's the equation (x^3-7x^2+4x+12); (x-2) use subsitution to tell whether the given binomial is a factor of the polynomial.
I keep getting just x^2 then I don't know what t
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-> SOLUTION: Hi here's the equation (x^3-7x^2+4x+12); (x-2) use subsitution to tell whether the given binomial is a factor of the polynomial.
I keep getting just x^2 then I don't know what t
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Question 483419: Hi here's the equation (x^3-7x^2+4x+12); (x-2) use subsitution to tell whether the given binomial is a factor of the polynomial.
I keep getting just x^2 then I don't know what to do Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! (x^3-7x^2+4x+12); (x-2) use subsitution to tell whether the given binomial is a factor of the polynomial.
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Sub 2 for x. If f(2)=0, then x-2 is a factor
f(x) = x^3-7x^2+4x+12
f(2) = 2^3 - 7*2^2 + 4*2 + 12
= 8 - 28 + 8 + 12
= 0
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x-2 is a factor.
