SOLUTION: Hi, I have this problem to solve, and would really appreciate some help: |5-2x|>3
I have come to a solution of 4<x<1 but i really do have no idea. i'm having trouble with this
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-> SOLUTION: Hi, I have this problem to solve, and would really appreciate some help: |5-2x|>3
I have come to a solution of 4<x<1 but i really do have no idea. i'm having trouble with this
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Question 48335: Hi, I have this problem to solve, and would really appreciate some help: |5-2x|>3
I have come to a solution of 4 Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! |5-2x|>3 [There are two conditions that must be considered in problems with absolute values: either x > 0 or x < 0]
|5-2x|>3 [First condition where x>+3]
5-2x>3 [Solve for x]
-5 + 5-2x>3-5
-2x>-2
-2x/-2<-2/-2 [Switch the sign when multiplying or dividing by a negative number]
x<1
.
|5-2x|>3 [Second condition where x<-3]
5-2x<-3
5-2x<-3 [Solve for x]
-5+5-2x<-3-5
-2x<-8
-2x/-2>-8/-2 [Switch the sign when multiplying or dividing by a negative number]
x>4
.
So, x<1 or x>4
