I take this to be interpreted as:
What is the probability that the sum of the numbers on the dice
is divisible by 3, given that it is a two digit number?
If that is the correct interpretation, then since we are given
that the sum is a two-digit number, the sum can only be 10, 11,
or 12, the ones colored red below:
⚀⚀ ⚀⚁ ⚀⚂ ⚀⚃ ⚀⚄ ⚀⚅
⚁⚀ ⚁⚁ ⚁⚂ ⚁⚃ ⚁⚄ ⚁⚅
⚂⚀ ⚂⚁ ⚂⚂ ⚂⚃ ⚂⚄ ⚂⚅
⚃⚀ ⚃⚁ ⚃⚂ ⚃⚃ ⚃⚄ ⚃⚅
⚄⚀ ⚄⚁ ⚄⚂ ⚄⚃ ⚄⚄ ⚄⚅
⚅⚀ ⚅⚁ ⚅⚂ ⚅⚃ ⚅⚄ ⚅⚅
Since we are given that the sum is a two-digit number, we can take
away all the rolls whose sum is not a 2-digit, but only a a 1-digit
number, and we will just have the red ones left as our reduced
sample space:
⚃⚅
⚄⚄ ⚄⚅
⚅⚃ ⚅⚄ ⚅⚅
And the only one of those rolls whose sum is divisible by 3 is
the one whose sum is 12, ⚅⚅.
That's 1 out of 6.
Answer 1/6.
Edwin