SOLUTION: Frankie has 22 coins in pocket worth a total of $4.75. If Frankie only has dimes and quarters in his pocket, how many of each does he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Frankie has 22 coins in pocket worth a total of $4.75. If Frankie only has dimes and quarters in his pocket, how many of each does he have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 483205: Frankie has 22 coins in pocket worth a total of $4.75. If Frankie only has dimes and quarters in his pocket, how many of each does he have?
Answer by gabriel24(6) About Me  (Show Source):
You can put this solution on YOUR website!
let x = no. of dimes (1 dime = 10 cents)
y = no. of quarters (1 quarter = 25 cents)
x + y = 22 coins
x = 22 - y (eq. 1)
0.1x + 0.25y = 4.75 (eq. 2)
SUBSTITUTE eq. 1 to eq. 2
0.1(22 - y) + 0.25y = 4.75
2.2 - 0.1y + 0.25y = 4.75
-0.1y + 0.25y = 4.75 - 2.2
0.15y = 2.55
y = 17 total number of quarters
x = 22 - y
x = 22 - 17
x = 5 total number of dimes