Question 482907: Please Help me: Household income does not tend to follow a normal distribution in a particular state, yet average income is approximately $45,000/year in this state, with a standard deviation of about $9000. Approximately what percentage of household incomes in this state is between $27,000 to $63,000/year? Show all work as to how this is obtained.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Household income does not tend to follow a normal distribution in a particular state, yet average income is approximately $45,000/year in this state, with a standard deviation of about $9000. Approximately what percentage of household incomes in this state is between $27,000 to $63,000/year? Show all work as to how this is obtained.
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(27000-45000)/9000 = -2
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(63000-45000)/9000 = 2
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Using Chebychev's approximation, (1-(1/2)^2)% = 0.75% of the
households will fall in that range.
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Cheers,
Stan H.
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