SOLUTION: I need to graph Y= log1/2(x-1)+3 and I need to find the intercepts. note the 1/2 is small at the bottom of the g

Algebra ->  Graphs -> SOLUTION: I need to graph Y= log1/2(x-1)+3 and I need to find the intercepts. note the 1/2 is small at the bottom of the g      Log On


   

Question 48279: I need to graph Y= log1/2(x-1)+3
and I need to find the intercepts.
note the 1/2 is small at the bottom of the g
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Y+=+log%281%2F2%2C%28x+-+1%29%29+%2B+3
x-intecept:
0+=+log%281%2F2%2C%28x+-+1%29%29+%2B+3
-3+=+log%281%2F2%2C%28x+-+1%29%29
%281%2F2%29%5E%28-3%29+=+x+-+1
8+=+x+-+1
9+=+x
P(9,0)
y-intercept:
Y+=+log%281%2F2%2C%28x+-+1%29%29+%2B+3
Y+=+log%281%2F2%2C%28-1%29%29+%2B+3 You can not take a log[] or a negative number.
graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Clog%280.5%2C%28x+-+1%29%29+%2B+3%29