Question 4827: Find three consecutive even integers such as that twice the sum of the first and second is 10 more then three times the third.
Answer by ichudov(507)   (Show Source):
You can put this solution on YOUR website! Any problem with word "consecutive integers" should make you think about:
x, x+1, x+2, ...
Any problem with word "consecutive even integers" should make you think about:
x, x+2, x+4, ...
x is the first number, and x+2, x+4, etc are next consecutive even number.
Next, you translate English into Algebrese:
first: x
second: x+2
twice the sum of the first and second: 2*(x+(x+2))
three times the third: 3*(x+4)
10 more: 10+
2*(x+(x+2)) = 10 + 3*(x+4)
2x+2x+4 = 10 + 3x + 12
2x+2x-3x = 10 + 12 - 4
x = 18
please double check that my solution is correct.
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