SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 104 miles per hour. Train A passes a

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 104 miles per hour. Train A passes a      Log On


   

Question 482519: Train A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 miles per hour and train B is traveling at 104 miles per hour. Train A passes a station at 3:10 pm If train B passes the same station at 3:40 pm at what time will train B catch up to train A?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Train A 100 mph
Train B 104 mph
Train A 03:10
Train B 03:40
Difference in time= 00:30 => 0.5 hours
Train A will have covered 50miles before Train B starts from station
catch up distance= 50 miles
catch up speed = 104 -100 mph
catch up speed = 4 mph
Catchup time = catchup distance/catch up speed
catch up time= 50 / 4
catch up time= 12.5 hours
It will catch up at 04:10 a.m.
m.ananth@hotmail.ca