SOLUTION: John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mph and travels 35 mi farther than Mary, who drives at 40 mph. Mary's trip take
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Question 48238This question is from textbook College Algebra
: John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mph and travels 35 mi farther than Mary, who drives at 40 mph. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?
Thank so very very much again! This question is from textbook College Algebra
You can put this solution on YOUR website! John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mph and travels 35 mi farther than Mary, who drives at 40 mph. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?
Draw the picture.
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John DATA:
Distance= x+35 miles ; rate= 60 mi/hr ; time = d/r = (x+35)/60
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Mary DATA:
Distance = x miles ; rate= 40 mi/hr ; time = d/r = x/40 hr
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EQUATION:
Mary's time - John's time = (1/4) hr.
(x/40)-(x+35)/60 = (1/4)
Multiply thru by 4 to get:
=x/10 - (x+35)/15 = 1
Multiply thru by 150 to get
15x-10x-350 = 150
5x=500
x=100
Mary's time = 100/40 = 2.5 hr.
John's time = (135/60) =2.25 hr.
Cheers,
Stan H.
x=100
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