Question 482299: According to the US Census Bureau, the total 2008 US population was 303,824,640. The 2008 population for five US States follows:
Missouri 5,911,605
Pennsylvania 12,448,279
Tennessee 6,214,888
Utah 2,736,424
Washington 6,549,224
What is the probability that a randomly selected US resident DID NOT live in Utah? Please show step by step so I will understand how this is worked.
TY,
Mary
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! According to the US Census Bureau, the total 2008 US population was 303,824,640. The 2008 population for five US States follows:
Missouri 5,911,605
Pennsylvania 12,448,279
Tennessee 6,214,888
Utah 2,736,424
Washington 6,549,224
What is the probability that a randomly selected US resident DID NOT live in Utah?
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P(not live in Utah) + P(live in Utah) = 1
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P(not live in Utah) = 1 - P(live in Utah)
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P(not live in Utah) = 1 - [2736424/303824640]
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P(not live in Utah) = 1 - 0.0090
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P(not live in Utah) = 0.9910
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Cheers,
Stan H.
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