Question 48220This question is from textbook College Algebra
: The admission fee at an amusement park is $1.50 for children and $4.00 for adults. On a certain day, 2200 people entered the park, and the admission fees collected totaled $5,050. How many children and how many adults were admitted?
Thank you so very much!
This question is from textbook College Algebra
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The admission fee at an amusement park is $1.50 for children and $4.00 for adults. On a certain day, 2200 people entered the park, and the admission fees collected totaled $5,050. How many children and how many adults were admitted?
$1.50 ticket DATA:
# of tickets used = x ; value of these tickets = 1.5x dollars
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$4.00 ticket DATA:
# of tickets used = 2200-x ; value of these tickets = 4(2200-x)=8800-4x dollars
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EQUATION:
value + value = $5,050
1.5x + 8800-4x = 5050
-2.5x = -3750
x=1500 ( # of $1.50 tickets = # of children admitted)
2200-1500 = 700 (# of adults admitted)
Cheers,
Stan H.
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